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We have x grams of N2 with 6g of H2 after reactions reveals 2 moles of NH3 formed. What is x?

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\\\text{The balanced reaction is as follows: } \\ \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3} \\ x \mathrm{g} \quad 6 \mathrm{g} \quad 34 \mathrm{g} \\ \text{Here, required nitrogen is 28 g }

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