Get Answers to all your Questions

header-bg qa

What is the hybridization of beryllium in \mathrm(B_{e}Cl_{2}) ?

Option: 1

sp


Option: 2

sp2


Option: 3

sp3


Option: 4

sp3d


Answers (1)

best_answer

In \mathrm {BeCl_{2}}, beryllium forms two covalent bonds with two chlorine atoms. The molecular shape of \mathrm {BeCl_{2}} is linear, indicating that the two bonds are oriented 180 degrees apart from each other. This arrangement suggests that the valence orbitals of beryllium are hybridized to form two sp hybrid orbitals. Each of these sp hybrid orbitals contains one unpaired electron, which is used to form a covalent bond with a chlorine atom, resulting in the formation of two Be-Cl covalent bonds in \mathrm {BeCl_{2}} .

Posted by

Shailly goel

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks