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What will be the ploidy of endosperm and zygote if the cross is made between 6n plant and 4n plant?
5n, 8n
8n, 5n
10n, 7n
6n, 4n
Answers (1)
When a cross is made between a 6n (hexaploid) female plant and a 4n (tetraploid) male plant, the ploidy of the resulting endosperm and zygote would be as follows:
The male plant has a ploidy level of 4n, meaning it has four sets of chromosomes.
During fertilization, the male gamete (pollen) with a ploidy level of n combines with the female gamete (egg) with a ploidy level of n to form a zygote. In this case, the zygote would have a ploidy level of 5n because it receives three sets of chromosomes from the female parent (6n) and two sets of chromosomes from the male parent (4n).
The endosperm, which provides nutrients to the developing embryo, typically results from the fusion of a haploid male gamete with two haploid female polar nuclei. In this particular cross, the ploidy level of the endosperm would be 8n. This is because the endosperm inherits two sets of chromosomes from the male parent (4n) and six sets of chromosomes from the female parent (6n).
To summarize:
The ploidy of the zygote is 5n.
The ploidy of the endosperm is 8n.
Hence, the correct answer is option 2.
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