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  • When 2 kg of ice at 0 °C melts to water at 0 °C, the resulting change in its entropy, taking latent heat of ice to be 80 Cal/oC, is:Optio

When 2 kg of ice at 0 °C melts to water at 0 °C, the resulting change in its entropy, taking latent heat of ice to be 80 Cal/oC, is:

Option: 1

586 cal/K


Option: 2

273 cal/K


Option: 3

8 x 104 cal/K


Option: 4

80 cal/K


Answers (1)

best_answer

As learnt in

Entropy for solid and liquid -

When heat is given to a substance to change its state at constant temperature.

- wherein

Delta S= frac{mL}{T}

L= Latent , Heat

T in kelvin

 

 \Delta S = \frac{\Delta Q}{T} = \frac{mL}{T}

          = \frac{2000\times 80}{273}\ cal/K

          = 586\ cal/K

Posted by

Gunjita

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