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When Air undergoes an adiabatic process, its temperature and volume are related by the equation TV^{n}= constant, the value of n will be:

Option: 1

0.4


Option: 2

0.33


Option: 3

2.33


Option: 4

1.4


Answers (1)

best_answer

For adiabatic process.

TV^{\gamma -1}= constant

For Air, since it majorly consists of N2 and O2, it can be considered as diatomic

\therefore \gamma= 1.4

Hence,

n= \gamma -1

    =1.4-1=0.4

 

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