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When 1 \mathrm{gm} of water changes from liquid to vapour phase at constant pressure of 1 atmosphere, the volume increases from \mathrm{1\mathrm{~cm}^3\: to\: 1671}  c.c. The heat of vaporization at this pressure is \mathrm{540 \mathrm{cal} / \mathrm{gm}}. Find Increase in internal energy of water.
 

Option: 1

2099.33 \mathrm{~J}
 


Option: 2

\quad 3099.33 \mathrm{~J}
 


Option: 3

4099.33 \mathrm{~J}


Option: 4

\quad 5099.33 \mathrm{~J}


Answers (1)

best_answer

From 1^{\text {st }} law of thermodynamics

\mathrm{ \Delta Q=\Delta U+\Delta W }

\mathrm{ \Delta Q=m L=1 \times 540 \mathrm{cal} }

\mathrm{ =2268 \mathrm{~J},[1 \mathrm{cal}=4.2 \mathrm{~J}] }

\mathrm{ \text { so, } \Delta \mathrm{U}=\Delta Q-\Delta \mathrm{W} }

\mathrm{ =(2268-168.67) \mathrm{J} }

\mathrm{ =2099.33 \mathrm{~J} }







 

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chirag

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