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When the spring is stretched 2 cm, it stores 100 J of energy. If it is stretched further by 2 cm, the stored energy increases by


Option: 1

100 J 



Option: 2

200 J



Option: 3

300 J 



Option: 4

400 J



Answers (1)


The energy stored in a spring that is stretched or compressed is given by the formula:

E=\frac{1}{2} k x^2

where E is the stored energy, k is the spring constant, and x is the displacement from the equilibrium position.

\frac {1}{2} k x^2=100

The work done in stretching of spring,

W =\frac{1}{2} k\left(x_2^2-x_1^2\right)

       \\ =\frac{1}{2} k\left((2 x)^2-x^2\right) \\ =3 \times\left(\frac{1}{2} k x^2\right) \\ =3 \times 100 \\\ =300 \mathrm{~J}

The stored energy will be increased by the amount of work done. 

Posted by

Shailly goel

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