Which of the following is an example of the anomalous behavior of boron?
Boron forms ionic compounds with halogens.
Boron does not exhibit any oxidation states other than +3.
Boron forms covalent compounds with hydrogen.
Boron has a low ionization energy compared to other Group 13 elements.
Boron exhibits anomalous behavior compared to other Group 13 elements in that it forms covalent compounds with hydrogen instead of ionic compounds. This is due to the small size of the boron atom, which allows it to form strong covalent bonds with hydrogen. Hence option C is the correct answer.
Option (A) is incorrect because boron does not typically form ionic compounds with halogens. Hence option A is incorrect.
Option (B) is incorrect because boron can exhibit a wide range of oxidation states, including negative and fractional oxidation states. Hence option B is incorrect.
Option (D) is incorrect because boron has a high ionization energy compared to other Group 13 elements. Hence option D is incorrect.