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Why does \mathrm{ F_2 } not accept electrons from \mathrm{ \mathrm{F}^{-}} ions to form \mathrm{\mathrm{F}_3{ }^{-}}ions as seen in case of \mathrm{\mathrm{I}_2} ?

Option: 1

\mathrm{F_2} has no vacant d -orbitals that can accommodate the electrons from \mathrm{\mathrm{F}^{-}} ions.
 


Option: 2

\mathrm{F_2} is less electronegative than \mathrm{\mathrm{F}^{-}}ions.
 


Option: 3

\mathrm{F_2} has a lower ionization energy than \mathrm{F}^{-} ions.
 


Option: 4

none of the above.


Answers (1)

best_answer

\mathrm{I}_2, because of the presence of vacant \mathrm{d} - orbitals, accepts electrons from \mathrm{\mathrm{I}^{-}} ions to form \mathrm{\mathrm{I}_3^{-}} ions but \mathrm{F}_2 because of the absence of \mathrm{d} - orbitals does not accept electrons from \mathrm{\mathrm{F}^{-}} ions to form \mathrm{\mathrm{F}_3^{-}} ions.

Posted by

vishal kumar

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