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Why is the bond angle in  \mathrm{NF}_3 smaller than the bond angle in  \mathrm{NH}_3  ? 

Option: 1

The electronegativity of \mathrm{F} is greater than the electronegativity of \mathrm{\mathrm{H}.}


Option: 2

The lone pair in \mathrm{NF}_3 causes a greater distortion from tetrahedral than the lone pair in \mathrm{NH}_3.

 


Option: 3

The bond angle in \mathrm{NF}_3 is determined by the repulsion between the lone pair and the bonding pairs.
 


Option: 4

The bond angle in \mathrm{NH}_3 is determined by the repulsion between the bonding pairs.


Answers (1)

best_answer

The electronegativity of \mathrm{F} is greater than the electronegativity of \mathrm{H}, but this does not have a significant effect on the bond angle. The main reason for the smaller bond angle in \mathrm{NF}_3 is that the lone pair in \mathrm{NF}_3 causes a greater distortion from tetrahedral than the lone pair in \mathrm{NH}_3. This is because the lone pair in \mathrm{NF}_3 is more electronegative than the lone pair in \mathrm{NH}_3, so it repels the bonding pairs more strongly.

Posted by

Irshad Anwar

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