Q7. Simplify

    (i)  \frac{25\times t^{-4}}{5^{-3}\times 10\times t^{-8}}\;\;(t\neq 0)

Answers (1)

The detailed solution for the above-written question is as follows

\frac{25\times t^{-4}}{5^{-3}\times 10\times t^{-8}}\;\;(t\neq 0)

we can write 25= 5^{2}

So, after rewriting the equation,

\frac{5^{2}\times t^{-4}}{5^{-3}\times 10\times t^{-8}}

= \frac{5^{2+3}\times t^{-4+8}}{10}.................using the form   [a^{m}\div a^{n}= a^{m-n}]

= \frac{5^{5}\times t^{4}}{10} .............(By expanding we have now)

= \frac{625t^{4}}{2}

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