Q 1.     A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

Answers (1)

The total mass of the compound = 0.24 g

Mass of boron in the compound = 0.096 g

Mass of oxygen in the compound = 0.144 g

Now, As we know,

The percentage of an element in the compound :

 =\frac{total\:mass\:of\:element}{total\:mass\:of\:compound}\times 100

So,

The percentage of Boron in the compound by weight :

=\frac{0.096}{0.24}\times 100

=40\%

The percentage of Oxygen in the compound by weight :

=\frac{0.144}{0.24}\times 100

=60 \%

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