Get Answers to all your Questions

header-bg qa

9.(iii)    A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at               random. What is the probability that the marble taken out will be not (iii) green?

Answers (1)



Total number of balls in the bag = 5 + 8 + 4 = 17

(iii) Let G be the event that the ball taken out is green

The number of possible outcomes = 17 

The number of outcomes favourable to the event G = 4

\therefore P(G) = \frac{favourable\ outcomes}{total\ outcomes}=\frac{4}{17}

\\ \therefore P(not\ G) =P(\overline G) =1-P(G) \\ = 1-\frac{4}{17} \\ = \frac{13}{17}

The required probability of not getting a green ball is \frac{13}{17}

Posted by


View full answer