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(a) Consider the circuit in Figure. How much energy is absorbed by electrons from the initial state of no current (ignore thermal motion) to the state of drift velocity?

(b) Electrons give up energy at the rate of RI_2  per second to the thermal energy. What time scale would one associate with energy in problem (a)? n = no of electron/volume = 10^{29}/m^3, length of circuit = 10 cm, cross-section = A = (1mm)^2

Answers (1)

a)

A=10^{-6}m^2

R=6\Omega

n=10^{29} m^{-3}

e=1.6\times 10^{-19}C
I=\frac{V}{}R=1A

m_e=9.1\times10^{-31}Kg

L=10^{-1}m

a) I=Anev_d
v_d=\frac{I}{Ane}=6.25\times 10^{-5}m/s
Kinetic energy=

 \frac{1}{}2\times m_e\times v_d^2=2\times 10^{-17}J

b) Power loss=

 I^2R=6W 
P=\frac{E}{}t
t=\frac{E}{}P=10^{-17}s

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