# Q5. A farmer has enough food to feed $20$  animals in his cattle for $6$ days. How long would the food last if there were$10$ more animals in his cattle?

The farmer has 20 animals to feed for 6 days and after that farmer added 10 more animals to feed that counts to (20+10 = 30). So, assume that food will now long last to 'x' days.

As the number of animals increases the required food increases but the day up to which the food will long last decreases.

Hence there exist an inverse proportion between the number of days and the number of animals.

So, we can write the relation as:

$20\times 6 = 30\times x$     or    $x= 4$ days.

The food will last for about 4 days if 30 animals are there.

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