# Q9   A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder         from base of the wall.

S seema garhwal

OA is wall and AB is ladder.

In $\triangle$ AOB, by pythagoras theorem

$AB^2=AO^2+BO^2$

$\Rightarrow 10^2=8^2+BO^2$

$\Rightarrow 100=64+BO^2$

$\Rightarrow 100-64=BO^2$

$\Rightarrow 36=BO^2$

$\Rightarrow BO=6 m$

Hence, the distance of the foot of the ladder from the base of the wall is 6 m.

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