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Q9   A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder
        from base of the wall.

Answers (1)

best_answer

OA is wall and AB is ladder.

In \triangle AOB, by pythagoras theorem

AB^2=AO^2+BO^2

\Rightarrow 10^2=8^2+BO^2

\Rightarrow 100=64+BO^2

\Rightarrow 100-64=BO^2

\Rightarrow 36=BO^2

\Rightarrow BO=6 m

Hence, the distance of the foot of the ladder from the base of the wall is 6 m.

 

 

 

 

 

 

 

Posted by

seema garhwal

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