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10(ii)   A piggy bank contains hundred 50p coins, fifty Rs 1 coins, twenty  Rs 2 coins and ten Rs  5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will not be a Rs 5 coin?

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Total number of coins in the piggy bank = 100+50+20+10 = 180

Let F be the event of getting an Rs. 5 coin.

Number of possible outcomes = 180

Number of outcomes favourable to event E = 10

\therefore P(F) = \frac{favourable\ outcomes}{total\ outcomes} = \frac{10}{180}

= \frac{1}{18}

\therefore P(not\ getting\ a\ Rs.\ 5\ coin )=P(\overline F)

= 1 - P(F) = 1 - \frac{1}{18} = \frac{17}{18}

Therefore, the probability of not getting an Rs. 5 coin is \frac{17}{18}

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