Q. 15. A stone is thrown vertically upward with an initial velocity of Taking find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
Initial velocity u = 40 m s-1
Acceleration a = -g = -10 m s-2
Final velocity at the highest point would be v = 0
Let the maximum height reached be s
As per the third equation of motion
The net displacement would be zero as the stone will return to the point from where it was thrown.
The total distance covered by the stone = 2s = 160 m
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