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Q 1.22 (a): A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of  80.0\frac{\mu C}{m^{2}} . (a) Find the charge on the sphere. 

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Given,

Surface charge density =  80.0\mu Cm^{-2}

Diameter of sphere = 2.4 m  \therefore Radius of sphere, r = 1.2 m

The charge on the sphere, Q= Surface charge density x Surface area of the sphere

= (80\times10^{-6})\times(4\pi r^2) = 320\times22/7\times(1.2)^2 = \boldsymbol{1.45\times10^{-3}\ C} 

Posted by

HARSH KANKARIA

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