An aromatic compound ‘A’ (Molecular formula ) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollens or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula ), which is also formed along with the yellow compound in the above reaction. Identify A, B and C and write all reactions involved.
Molecular formula of the compound in question is It is given that ‘A’ does not give Tollens’ or Fehling’s test, making it a ketone. Since we get positive test with 2, 4-DNP and iodoform test, It means it is methyl ketone.