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Arrange the following H-H D-D and F-F in order of increasing bond dissociation enthalpy

9.16 arrange the following 

(iii) H–H, D–D and F–F in order of increasing bond dissociation enthalpy

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R Rakesh

Answer-

F-F<H-H<D-D  increasing order of bond dissociation enthalpy

In F-F high repulsion force is acting so breaking should be easy.

while in case of H-H and D-D, bond pair of D-D is more strongly attracted by the nucleus because of the higher nucleus mass in D2. we know that higher the attraction high is the bond strength.

 

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