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Arrange the following NaH, MgH2, and H2O in order of increasing reducing property

Arrange the following  NaH, MgH_2, and H_2O in order of increasing reducing property

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R Rakesh

Answer-

increasing order of reducing property-

 H_{2}O<MgH_{2}<NaH

Na can easily donate electrons so it has a higher reducing property. Both  H_{2}OandMgH_{2} are covalent hydrides. water has less reducing property because it has high bond dissociation energy than MgH_{2}

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