Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium: 2BrCl (g) Br_2 (g) + Cl_2 (g) for which K_c = 32 at 500 K. If initially pure BrCl is present at a concentration of 3.3

7.22     Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium:

                2BrCl_{(g)}\rightleftharpoons Br_{2}_{(g)}+Cl_{2}_{(g)}

For which Kc = 32 at 500 K. If initially pure BrCl is present at a concentration of 3.3 × 10-3 mol L-1, what is its molar concentration in the mixture at equilibrium?

Answers (1)

best_answer

Suppose the x amount of bromine and chlorine formed at equilibrium. The given reaction is:

                    2BrCl_{(g)}\rightleftharpoons Br_{2}_{(g)}+Cl_{2}_{(g)} 

Initial Conc.     3.3\times10^{-3}          0            0

at equilibrium   3.3\times10^{-3}- 2x    x          x

Now, we can write,

K_c =\frac{[BR_2][Cl_2]}{[BrCl_2]^2}
32=\frac{x^2}{(3.3\times 10^{-3}-2x)^2}
5.66=\frac{x}{(3.3\times 10^{-3}-2x)}
x+11.32x=18.678 \times 10^{-3}

By solving the above equation we get, 

       x = 1.51 \times 10^{-3}

Hence, at equilibrium [BrCl_2] = 3.3\times 10^{-3} - (2\times 1.51\times 10^{-3})
                                                      = 0.3\times 10^{-3} M

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question