Calcium chloride when dissolved in water dissociates into its ions according to the following equation.
CaCl_{2} (aq) \rightarrow Ca^2+ (aq) + 2Cl^{-} (aq)
Calculate the number of ions obtained from CaCl_{2} when 222 g of it is dissolved in water.

Answers (1)

Answer:

111g(1mole)\rightarrow 1mole+2moles
222g(2mole)\rightarrow 2moles+2moles
Total number of ions by 2 moles of CaCl_{2} = 6
Number of ions = Number of moles of ions \times N_{A}
                               =6\times 6.023\times 10^{23}
                               =3.6132\times 10^{24} ions

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