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Calculate potential on the axis of a ring due to charge Q uniformly distributed along the ring of radius R.

Answers (1)

Here, in the above image, point P is perpendicular to O and is at a distance of z from point O, which is the centre of the ring.

The charge dq is at a distance z from the point P.

Therefore, V can be written as:

V=\frac{1}{4\pi \epsilon _{0}}\int \frac{dq}{r}=\frac{1}{4\pi \epsilon _{0}}\int \frac{dq}{\sqrt{z^{2}+a^{2}}}

Therefore, the net potential will be :

V=\frac{1}{4\pi \epsilon _{0}}\frac{Q}{\sqrt{z^{2}+a^{2}}}

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