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A capacitor has some dielectric between its plates, and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, the charge stored, and the voltage will increase, decrease, or remain constant.

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Quantity Battery is removed Battery remains connected
Capacity C'=KC


Charge Q'=Q


Potential V'=\frac{V}{K} V'V
Intensity E'=\frac{E}{K} E'=E
Energy U'=\frac{U}{K} U'=UK


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