Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Calculate the pH of the following solutions: (c) 0.3 g of NaOH dissolved in water to give 200 mL of solution.

7.49     Calculate the pH of the following solutions:

  (c)     0.3 g of NaOH dissolved in water to give 200 mL of solution. 

Answers (1)

best_answer

NaOH dissociates into NaOH\rightarrow Na^+ +OH^-
So, the concentration of [NaOH]  = \frac{0.3\times 1000}{200\times 40} M = 0.0375 M

\therefore [OH^-] = [NaOH] = 0.0375 M
 

We know that ,
[H^+] = \frac{K_w}{[OH^-]} = \frac{10^{-14}}{0.0375} = 2.66\times 10^{-13}

Now, P^H = - \log[H^+]
                  \\=- \log(2.66\times 10^{-13})\\ =12.57

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2027 LIVE: Kerala SSLC dates out; Assam, Bihar, Gujarat Class 10, 12 schedules awaited
anam-khan

CBSE Date Sheet 2027 (OUT) LIVE: Class 10, 12 exam dates out for over 46 lakh students; passing marks
anam-khan

CBSE Class 12 exams clash with Holi on March 22; will board revise date sheet?

Latest Question