Check the divisibility of the following numbers by 3.

    5. 927

Answers (1)

Any number will be divisible by 3 only if the sum of all the digits in that number will be divisible by 3.

Sum of digits of number 927 = 9 + 2 + 7 = 18 which is divisible by 3. 

Hence we conclude number 108 is divisible by 3.

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