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Check what the result would have been if Sundaram had chosen the numbers shown below. 1. 417

Check what the result would have been if Sundaram had chosen the numbers shown below.   

    Q1. 417

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Let choosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

After adding all the above three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c),

It will be divisible by 37 becuase 37 is present in the equation.

here a = 4, b = 1, and c = 7

417 + 741 + 147 = 1332 = 37*36  i.e. divisible by 37.

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