Check what the result would have been if Sundaram had chosen the numbers shown below.
Let choosen number be abc then,
abc = 100a + 10b + c
cab = 100c + 10a + b
bca = 100b + 10c + a
The addition of all above three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c), which is divisible by 37
here a = 9, b = 3, and c = 7
937 + 793 + 397 = 2109 = 37*57 i.e. divisible by 37.
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