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  • Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm.

Q 1.     Construct the right angled \Delta PQR, where \angle Q=90^{\circ}, QR = 8cm and PR = 10 cm.

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the right-angled \Delta PQR, where \angle Q=90^{\circ}, QR = 8cm and PR = 10 cm:

1. Draw QR = 8 cm

2. Draw a perpendicular QX to QR at Q

3. From R and with length = 10 cm cut an arc on QX. The arc meet QX at P 

4. Join PR

PQR is the required triangle

Posted by

Pankaj Sanodiya

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