Q 1.     Construct the right angled $\Delta PQR$, where $\angle Q=90^{\circ}$, QR = 8cm and PR = 10 cm.

P Pankaj Sanodiya

the right-angled $\Delta PQR$, where $\angle Q=90^{\circ}$, QR = 8cm and PR = 10 cm:

1. Draw QR = 8 cm

2. Draw a perpendicular QX to QR at Q

3. From R and with length = 10 cm cut an arc on QX. The arc meet QX at P

4. Join PR

PQR is the required triangle

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