Draw the following.
Q2. A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
Let ABCD be the rhombus such that:
AC = 6.4 cm (longer diagonal) and BD = 5.2 cm (shorter diagonal)
We know that the diagonals of a rhombus bisect (cut in half) each other perpendicularly, i.e at 60°
In other words, the midpoint of the diagonals coincide.
Steps of construction:
Step 1. Draw a line segment AC =6.4 cm. Now, construct the perpendicular bisector of AC. Let it intersect AC at O.
(Therefore, O is the midpoint of both the diagonals AC and BD)
Step 2. With O as center and radius half of BD = , draw two arcs on both sides of AC intersecting the perpendicular bisector at B and D.
Step 3. Join B to A and C. Also join D to A and C.
ABCD is the required rhombus.