Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Evaluate the integrals in Exercises 1 to 8 using substitution. dx/ (x^2+2x+5)

Evaluate the integrals in Exercises 1 to 8 using substitution.

    Q7.    \int_{-1}^1\frac{dx}{x^2 +2x + 5}

Answers (1)

best_answer

\int_{-1}^1\frac{dx}{x^2 +2x + 5}
the Dr can be written as x^2+2x+5 = (x+1)^2+2^2
and put x+1 = t then dx =dt

when x= -1 then t = 0 and when x = 1 then t = 2

\\\Rightarrow \int_{0}^{2}\frac{dt}{t^2+2^2}\\ =\frac{1}{2}[\tan^{-1}\frac{t}{2}]^2_0\\ =\frac{1}{2}( \pi/4)\\ =\frac{\pi}{8}

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th biology, physical education exams 2026 for sports event participants on April 11 and 13
anam-khan

CBSE 2026 Class 12 LIVE: History exam begins; paper pattern, guidelines, things to carry
anam-khan

CBSE introduces alternative assessment scheme for Class 12 students in West Asia; key guidelines

Latest Question