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  • Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions.

Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions.If the particle has a mass of 500g find the force (direction and magnitude) acting on the particle. 

 

Answers (1)

Looking at graph (a), we get

v_x = \frac{dx}{dt}= \frac{2}{2}=1 m/s

a_{x}=\frac{d^{2}x}{dt^{2}}=\frac{dv_{x}}{dt}=0

Looking at graph (b), we get

y = t^{2}

Thus, v_{y} = \frac{dy}{dt} = 2t

a_{y} = \frac{dv_{y}}{dt} = 2

Thus, F_{y} = ma_{y}   \therefore( m = 500g = 0.5 kg)

F_{y} = 0.5(2)

    = 1 N, towards \ Y-axis

F_{x} = 0.5(0)

     =0N

F = \sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{0^{2}+1^{2}}=\sqrt{1}

Hence, F = 1 N, towards the Y-axis.

Posted by

infoexpert24

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