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  • Find the mean deviation about the mean of the distribution:

1.Find the mean deviation about the mean of the distribution:

Size 20 21 22 23 24
Frequency 6 4 5 1 4



 

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\begin{array}{l} \bar{x}=\frac{\sum_{i=1}^{n} f_{i} x_{i}}{N}=\frac{433}{20}=21.65 \\ \\ M D=\frac{1}{N} \sum_{i=1}^{n} f_{i}\left|x_{i}-x\right|=\frac{1}{20} \times 25=1.25 \end{array}

 

Posted by

Satyajeet Kumar

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