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# Find the measure of each exterior angle of a regular polygon of (i) 9 sides

2. Find the measure of each exterior angle of a regular polygon of
(i) 9 sides

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A regular polygon of 9 sides have all sides,interior angles and exterior angles equal.

Sum of exterior angles of a polygon = $360\degree$

Let interior angle be A.

Sum of exterior angles of 9 sided polygon = $9 \ast A =$ $360\degree$

Exterior angles of 9 sided polygon$= A= 360\degree \div 9$

$A= 40\degree$

Hence, measure of each exterior angle of a regular polygon of 9 sides is $40\degree$

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