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# Find the remainder when x ^3 + 3x ^2 + 3x + 1 is divided by (iii) x

1.(iii) Find the remainder when $x^3 + 3x^2 +3x + 1$ is divided by

(iii)    $x$

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When we divide  $x^3 + 3x^2 +3x + 1$  by  $x$

By long division method, we will get

Therefore, remainder is  $1$

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