Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the slope of the tangent to the curve y = x ^3 – 3 x + 2 at the point whose x-coordinate is 3.

4) Find the slope of the tangent to the curvey = x ^3 - 3x +2 at the point whose x-coordinate is 3.

Answers (1)

best_answer

Given curve is,
y = x ^3 - 3x +2
The slope of the tangent at x = 3 is given by
\left ( \frac{dy}{dx} \right )_{x=3} = 3x^2 - 3 = 3(3)^2 - 3= 3\times 9 - 3 = 27 - 3 = 24
Hence, the slope of tangent at point x = 3 is 24

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Chemistry Paper Analysis: Students find exam easy, well-balanced; mostly previous year questions
anam-khan

CBSE Class 12: Delhi Government school teachers ask board to put on-screen marking system on hold
anam-khan

CBSE Board Exam 2026 LIVE: CBSE Class 12 Chemistry question paper analysis; answer key

Latest Question