# Q.10 Find the smallest square number that is divisible by each of the numbers $8,15$ and $20$.

This has to be done in two steps. First we will find LCM of given numbers, then we will make it perfect square.

So the LCM of 8, 15, 20 is 120   .                                  8 = 2$\times$2$\times$2  ;           15 = 3$\times$5   ;             20 =  2$\times$2$\times$5

Prime factorisation of 120 gives = $2\times2\times2\times3\times5$ .

To make it a perfect square we need to multiply it with 30.

So the smallest square number that is divisible by each of the numbers 4, 9 and 10 is 3600.

## Related Chapters

### Preparation Products

##### JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
##### Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
##### Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
##### Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-