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# Find the squares of the following numbers containing in units place. (ii) 95

Q. Find the squares of the following numbers containing 5 in unit’s place.

(ii) 95

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Assume a number with unit digit 5 = a5

$(a5)^{2}$ = $(10a + 5)^{2}$ = 10a(10a + 5) + 5(10a + 5) = 100a 2 + 50a + 50a + 25

= 100a(a + 1) + 25

= a(a + 1) hundred + 25

We are going to use this result here.

In this question a = 9

so,     $95^{2}$ = 9(9+1)hundred + 25

= 9000 + 25 = 9025

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