Q3. Find the value of.

    (ii) (2^{-1}\times 4^{-1})\div 2^{-2}

Answers (1)
M manish

The detailed explanation for the above-written question is as follows

Rewrite the equation

(2^{-1}\times 4^{-1})\div 2^{-2} = (2^{-1}\times 2^{-2})\div 2^{-2}

=(2^{-1+(-2)})\div 2^{-2}    .................................a^{m}\times a^{n}= a^{(m+n)}

=(2^{-3})\div 2^{-2} = 2^{-3-(-2)}........................a^{m}\div a^{n}= a^{(m-n)}

                              = 2^{-1}= \frac{1}{2}

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