Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the values of each of the expressions in Exercises 16 to 18. 17. tan inverse ( tan 3 pi / 4)

Find the values of each of the expressions in Exercises 16 to 18.

    17. \tan^{-1}\left (\tan\frac{3\pi}{4} \right )

Answers (1)

best_answer

As we know \tan^{-1}\left ( \tan x \right ) =x

If x \epsilon \left ( -\frac{\pi}{2}, \frac{\pi}{2} \right ). which is the principal value range of \tan^{-1}x.

So, as in \tan^{-1}\left (\tan\frac{3\pi}{4} \right );

\frac{3\pi}{4}\notin \left ( -\frac{\pi}{2}, \frac{\pi}{2} \right )

Hence we can write \tan^{-1}\left (\tan\frac{3\pi}{4} \right )   as :

\tan^{-1}\left (\tan\frac{3\pi}{4} \right ) = \tan^{-1}\left (\tan\frac{3\pi}{4} \right) = \tan^{-1}\left [ \tan(\pi - \frac{\pi}{4}) \right ] = \tan^{-1}\left [ \tan (\frac{-\pi}{4}) \right ]

Where -\frac{\pi}{4} \epsilon \left ( -\frac{\pi}{2}, \frac{\pi}{2} \right )

and \therefore \tan^{-1}\left (\tan\frac{3\pi}{4} \right )=\tan^{-1}\left [ \tan (\frac{-\pi}{4}) \right ]=-\frac{\pi}{4}

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 English Paper Analysis: Questions easy, ‘student-friendly’; can 'score above 90%'
anam-khan

CBSE Class 12 Board Exam 2026 LIVE: 12th English paper easy, 'competency-based questions' for literature
anam-khan

QR code in CBSE Class 12 maths paper redirects to 'rickroll' prank video; board says exam integrity intact

Latest Question