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Q. 6.    (b) From the sum of 4+3x and 5-4x+2x^{2},subtract the sum of 3x^{2}-5x and -x^{2}+2x+5.

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\\( 4 + 3x + ( 5 - 4x + 2x^2) ) - ( 3x^2 - 5x + ( -x^2 + 2x + 5) \\= (4 + 3x + 5 - 4x + 2x^2 ) - ( 3x^2 - 5x -x2 + 2x + 5) \\= 4 + 3x + 5 - 4x + 2x^2 - 3x^2 + 5x + x^2 - 2x - 5 \\=4 + 5 - 5 + ( 3 - 4 + 5 - 2 )x + ( 2 - 3 + 1 )x^2 \\=4 + 2x

On subtracting the sum of 3x^{2}-5x and -x^{2}+2x+5 from the sum of  4+3x and 5-4x+2x^{2} we get 4+2x

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