Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

3.20 (b) Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them
to get an equivalent resistance of (iv) $\frac{6}{11}\Omega$

Answers (1)

best_answer

Connect all three resistors in parallel.

Equivalent Resistance is R = 1/(1/1 + 1/2 + 1/3) = (1x 2 x 3)/(6 + 3 + 2)

R = 6/11 Ω

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

HD Video Lectures
Unlimited Mock Tests
Faculty Support

cuet_ads

Similar Questions

100 g of liquid A (molar mass 140 g mol^-1) was dissolved in 1000 g of liquid B (molar mass 180 g mol^-1).The vapour pressure of pure liquid B was found to be 500 torr.
100 turn rectangular coil ABCD (in X-Y plane) is hung from one arm of a balance (shown in figure). A mass 500 g is added to the other arm to balance the weight of the coil.
100m long antenna is mounted on a 500m tall building The complex can become a transmission tower for waves with λ (a) ~ 400 m (b) ~ 25 m (c) ~ 150 m (d) ~ 2400 m

Trending Articles/News

anam-khan

CBSE extends single girl child scholarship registration deadline till November 20

anam-khan

CBSE reminds schools to submit registration data of Class 9, 11 students by October 16

Latest Question