3.20 (b) Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (iv)
Connect all three resistors in parallel.
Equivalent Resistance is R = 1/(1/1 + 1/2 + 1/3) = (1x 2 x 3)/(6 + 3 + 2)
R = 6/11 Ω
CBSE reminds schools to submit registration data of Class 9, 11 students by October 16
CBSE reopens online portal for submission of LOC for Class 10, 12 board exams 2026; submit forms by Oct 8
CBSE private candidates challenge cancellation of post-Class 12 additional subject exam in Delhi HC
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now