# Q.5 How many elements has P(A), if A = $\phi$?

Let the elements in set A be m,then n$\left ( A \right ) =$ m

then, number of elements in power set of A         n$\left ( p\left ( A \right )\right ) =$ $2^{m}$

Here,  A = $\phi$   so    n$\left ( A \right ) =$ 0

n$\left [ P\left ( A \right ) \right ] =$ $2^{0}$ $=$1

Hence,we conclude P(A) has 1 element.

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