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let the number abc be 132
Here a = 1, b = 3 and c = 2
132= 100*1 + 10*3 + 2 = 99 + 11*3 + (1 - 3 + 2)
= 11(9*1+3) + (1 - 3 + 2 )
if number is divisible by 11 then (a - b + c ) must be divisible by 11.
as in above case of number 132 the a - b + c = 1 -3 + 2 = 0 whichis divisible by 11.
Hence we conclude ( a - b + c ) should be divisible by 11 if abc is divisible by 11.