Iceberg floats in water with part of it submerged. What is the fraction of the volume of iceberg submerged if the density of ice is \rho i = 0.917 \frac{g}{cm^{3}}?

Answers (1)

The weight of the iceberg is equal to the weight of the displaced liquid, as the iceberg is floating on the surface of the sea.

V Pi g = V Pw g

The volume of an iceberg submerged in water/ vol of iceberg = \frac{V^{'}}{V}=\frac{Pi}{Pw}=\frac{0.917}{1}

Hence the portion of the iceberg which is submerged in water is 0.917

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