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  • If – 3x + 17 < – 13, then A.x ∈ (10, ∞) B. x ∈ [10, ∞) C. x ∈ (–∞, 10] D. x ∈ [– 10, 10)

If 3x + 17 < -13 then 

A. x\epsilon \left ( 10,\infty \right )

B.x\epsilon \left ( 10,\infty \right )

C.x\epsilon \left ( -\infty,10 \right )

D.x\epsilon \left ( -10,10 \right )

Answers (1)

Given: 3x + 17 < -13

Now, we will subtract both sides by 17, we get,

-3x < -30

Now, we know that,

Multiplication or division by -ve no. Inverts the inequality sign

Thus, x > 10

Thus, x ∈ (10,\infty)

Posted by

infoexpert22

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