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  • If p(x) equal to x square minus 2 square root of 2x plus 1 , then p 2 square root of 2 is equal to (A) 0 (B) 1 (C) 4 square root of 2 (D) 8 square root of 2

If p(x)=x^{2}-2\sqrt{2}x+1 , then p\left (2\sqrt{2} \right )  is equal to 

(A) 0                          

(B) 1                           

(C) \left (4\sqrt{2} \right )                     

(D) \left (8\sqrt{2} \right )          

Answers (1)

(B) 1          

Solution:

p(x)=x^{2}-2\sqrt{2}x+1

p \left (2\sqrt{2} \right )  means that the value of x is 2\sqrt{2}

Put x=2\sqrt{2}  in the given equation

p \left (2\sqrt{2} \right )= \left (2\sqrt{2} \right )^{2}- \left (2\sqrt{2} \right ) \left (2\sqrt{2} \right )+1\\ p \left (2\sqrt{2} \right )= \left (2\sqrt{2} \right )^{2}- \left (2\sqrt{2} \right )^{2}+1\\ p \left (2\sqrt{2} \right )=1

Hence the value of p \left (2\sqrt{2} \right )  is 1.

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infoexpert24

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