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One of the zeroes of the polynomial 2x^{2}+7x-4  is 

(A) 2                          

(B) \frac{1}{2}                          

(C) -\frac{1}{2}                       

(D) -2            

Answers (1)

(B) \frac{1}{2}  

Solution

 We know that for finding the zero of a polynomial, we need to find a value of x for which the polynomial will be zero

 i.e., p(x)=0

 Here the polynomial is 2x^{2}+7x-4  

 Now let us find zeroes of this polynomial

 2x^{2}+7x-4=0\\ 2x^{2}+8x-x-4=0\\ 2x\left ( x+4 \right )-1\left ( x+4 \right )=0\\ \left ( x+4 \right )\left ( 2x-1 \right )=0\\ x=-4,x=\frac{1}{2} 

The zeros of the given polynomial are -4,\frac{1}{2}

Among the given options, (B) is correct.

 

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